Continuity and Differentiability Class 12 Subject Teacher - Search Videos

Q) Determine a and b if f(x) is a continuous function, where 𝑓(𝑥)={(2, ≤3 𝑎𝑥+𝑏, 3=𝑥=5 5, 𝑥≥5)

Q) Determine a and b if f(x) is a continuous function, where 𝑓(𝑥)={(2, ≤3 𝑎𝑥+𝑏, 3=𝑥=5 5, 𝑥≥5)

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$If 𝑓(𝑥)={ ((sin^2 𝑎𝑥)/𝑥^2 if 𝑥≠0 1 , if 𝑥=0) is continuous at 𝑥=0, then the value of ' 𝑎 ‘$

If 𝑓(𝑥)={ ((sin^2 𝑎𝑥)/𝑥^2 if 𝑥≠0 1 , if 𝑥=0) is continuous at 𝑥=0, then the value of ' 𝑎 ‘

1.8K views1 month ago

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Q) Show that the derivative of tan^(−1) (sec𝑥+tan𝑥),[−𝜋/2𝑥𝜋/2] with respect to x is equal to 1

Q) Show that the derivative of tan^(−1) (sec𝑥+tan𝑥),[−𝜋/2𝑥𝜋/2] with respect to x is equal to 1

4.7K views1 month ago

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$Find k so that 𝑓(𝑥)={((𝑥^2−2𝑥−3)/(𝑥+1), 𝑥≠−1 𝑘, 𝑥=−1) is continuous at x=−1.#cbse2027 #maths$

Find k so that 𝑓(𝑥)={((𝑥^2−2𝑥−3)/(𝑥+1), 𝑥≠−1 𝑘, 𝑥=−1) is continuous at x=−1.#cbse2027 #maths

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$Q) If 𝑓(𝑥)={((1−sin^3 𝑥)/(3cos^2 𝑥), for 𝑥≠𝜋/2 𝑘, for 𝑥=𝜋/2) is continuous at 𝑥=𝜋/2, t$

Q) If 𝑓(𝑥)={((1−sin^3 𝑥)/(3cos^2 𝑥), for 𝑥≠𝜋/2 𝑘, for 𝑥=𝜋/2) is continuous at 𝑥=𝜋/2, t

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YouTubeShivang Maths Academy

For what value of k, the function given below is continuous at x = 0? 𝐟(𝐱)={((√(𝟒+𝐱)−𝟐)/𝐱,

For what value of k, the function given below is continuous at x = 0? 𝐟(𝐱)={((√(𝟒+𝐱)−𝟐)/𝐱,

2.1K views1 month ago

YouTubeShivang Maths Academy

Q) Find the value of 𝑘, so that 𝑓(𝑥)={(𝑘cos𝑥/(𝜋−2𝑥), if 𝑥≠𝜋/2@3, if 𝑥=𝜋/2) is continu

Q) Find the value of 𝑘, so that 𝑓(𝑥)={(𝑘cos𝑥/(𝜋−2𝑥), if 𝑥≠𝜋/2@3, if 𝑥=𝜋/2) is continu

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YouTubeShivang Maths Academy

Q) If 𝑓(𝑥)={(1,if 𝑥≤3 𝑎𝑥+𝑏, if 3 ≤𝑥≤ 7, if 5≤𝑥) is continuous in 𝑅, then the values of

1.4K views1 month ago

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Q) If tan^(−1) 𝑥=𝑦, then 𝑑𝑦/𝑑𝑥 is equal to #continuity_and_differentiability #maths #cbse

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Q) The value of 𝑘 for which the function 𝑓(𝑥)={(𝑥^2 sin 1/𝑥, 𝑥≠0 𝑘(𝑥+1), 𝑥=0) is a continuo

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YouTubeShivang Maths Academy

Q) If y={x+√(x^2−a^2 )}^n, then prove that dy/dx=ny/√(x^2−a^2 )#cbse2027 #maths #cbse #cbseclass12

3.2K views2 weeks ago

YouTubeShivang Maths Academy

If 𝑥√(1+y)+y√(1+𝑥)=0,, then prove that dy/dx=(−1)/((1+x)^2 ) )#maths #cbse2026

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