The way I would normally do this problem is let u=(cosx), so du=sinxdx Then its just the Integral of u^2? No? With 1/sinx pulled outside of the integral. This is easy to integrate, but apparently is ...

👉 Learn how to evaluate the integral of a function. The integral, also called antiderivative, of a function, is the reverse process of differentiation. Integral of a function can be evaluated as an ...

Keywords 👉 Learn how to evaluate the integral of a function. The integral, also called antiderivative, of a function, is the reverse process of differentiation. Integral of a function can be ...

Note: This only works when \(x\) is measured in radians. We are now going to look at more complex trigonometric functions where we will use the general rule: \(\int {\cos (ax + b)dx = \frac{1}{a}} ...

Remember that integration is the inverse procedure to differentiation. So, if you can do trigonometric differentiation, you can do trig integration.